tag:blogger.com,1999:blog-166849791284017995.post8695831338903879114..comments2024-03-13T07:44:47.020-07:00Comments on psu-matematicas: Desafío - RaícesUnknownnoreply@blogger.comBlogger1125tag:blogger.com,1999:blog-166849791284017995.post-87635793356474503222009-11-26T18:58:25.794-08:002009-11-26T18:58:25.794-08:00=
((3^n)(3²+3))/((12^n)*12)^(1/n) =
((3^n)(12))/...=<br /><br />((3^n)(3²+3))/((12^n)*12)^(1/n) =<br /><br />((3^n)(12))/((12^n)*12)^(1/n) =<br /><br />((3^n)/(12^n))^(1/n) =<br /><br />((1^n)/(4^n))^(1/n) =<br /><br />1/4<br /><br />Alternativa c<br /><br />[img]http://www.fileden.com/files/2008/9/18/2103783/Sin%20nombre.png[/img]Totoxahttps://www.blogger.com/profile/04305282199630897217noreply@blogger.com